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6502

Revision as of 11:50, 14 September 2024 by Phi2x (Talk | contribs) (Chip Variants)

The 6502 CPU

The MOS Technology 6502 is an 8-bit microprocessor designed by Chuck Peddle in 1975 for MOS Technology (later purchased by Commodore). When it was introduced it was the least expensive full featured CPU on the market by far, at about 1/6th the price, or less, of competing designs from larger companies such as Motorola and Intel. It was nevertheless faster than most of them, and, along with the Zilog Z80, sparked off a series of computer projects that would eventually result in the home computer revolution of the 1980s. The 6502 design was originally second-sourced by Rockwell and Synertek and later licensed to a number of companies; it is still made for embedded systems.

Originally the CPC was destined to be designed around the 6502 processor. But when Amstrad approached Locomotive Software to develop a Basic for it with a very tight deadline, Locomotive PLC, who already had a Z80 Basic in the works, urged and convinced Amstrad to switch to the Z80.


Description

The 6502 microprocessor is an 8-bit CPU with an 8-bit ALU and a 16-bit address bus capable of direct access to 64KB of memory space. Like the Z80, the 6502 is a little-endian CPU, meaning it stores 16-bit values with the least significant byte first, followed by the most significant byte. The 6502 has 151 instructions, which are composed of 56 distinct opcodes across various addressing modes.

Although it lacks the raw processing power of processors like the Intel 80x86 or the Motorola 68000 series, the 6502 was known for its efficiency and affordability, making it a popular choice for embedded systems and early home computers. Its simple design contributed to lower manufacturing costs and simplified integration.

The 6502 chip is made up of 4528 transistors (3510 enhancement transistors and 1018 depletion pullup transistors). Despite having so few transistors, it is generally viewed as being twice as fast as the Z80 for same clock speed. Two reasons explain it:

  • The 6502 has an 8-bit ALU while the Z80 has a 4-bit ALU
  • The 6502 has a clock doubler circuit built inside the chip

The 6502 comes in a 40-pin DIP package. It has been produced by various manufacturers and used in a wide range of applications, from gaming consoles like the Atari VCS, Atari Lynx, Nintendo Entertainment System and PC-Engine to personal computers like the Apple II, BBC Micro, Oric, VIC20 and Commodore 64.


Registers

Register Size Description Notes
A (Accumulator) 8-bit Main register for arithmetic, logic, and data transfer Most operations use this register
X (Index Register X) 8-bit Used for indexing memory and loop counters Can be used for addressing modes like Indexed Indirect, Zero Page Indexed, and Absolute Indexed
Y (Index Register Y) 8-bit Used for indexing memory and loop counters Often used in Absolute and Zero Page Indexed addressing
P (Processor Status) 8-bit
  • bit7 - NF - Negative Flag
  • bit6 - VF - Overflow Flag
  • bit5 - Unused (always set to 1)
  • bit4 - BF - Break Command
  • bit3 - DF - Decimal Mode Flag
  • bit2 - IF - Interrupt Disable Flag
  • bit1 - ZF - Zero Flag
  • bit0 - CF - Carry Flag
Flags are affected by most operations.

BF is not a physical flag implemented in a register. It only appears on the stack when the P register is pushed to it.

S (Stack Pointer) 8-bit Points to the current location in the stack Stack is located in page 1 ($0100-$01FF), 8-bit S register is offset to this base
PC (Program Counter) 16-bit Points to the next instruction to be executed Automatically increments as instructions are executed


IRQ / NMI / BRK / RESET

On a RESET, the CPU loads the vector from $FFFC/$FFFD into the program counter and continues fetching instructions from there.

On an NMI, the CPU pushes the low byte and the high byte of the program counter as well as the processor status onto the stack, disables interrupts and loads the vector from $FFFA/$FFFB into the program counter and continues fetching instructions from there.

On an IRQ, the CPU does the same as in the NMI case, but uses the vector at $FFFE/$FFFF.

On a BRK instruction, the CPU does the same as in the IRQ case, but sets bit #4 (B flag) in the copy of the status register that is saved on the stack.

The priority sequence for interrupts, from top priority to bottom, is as follows: RESET, BRK, NMI, IRQ. Source at chapter 7.19

On NMOS, NMI or IRQ that happens during specific moments of BRK execution can cause BRK to be effectively skipped. On CMOS, this situation is correctly handled by executing BRK and then servicing the interrupt.


Decimal Mode

BCD operations are limited to addition and subtraction using the ADC and SBC instructions.

On NMOS, when Decimal Mode is on, the ADC and SBC instructions update NF, VF and ZF based on the binary result before the decimal correction is applied. Only CF is updated correctly. On CMOS, all the flags are updated correctly, at the cost of 1 additional cycle.

On NMOS, DF is not defined after RESET. On CMOS, DF is automatically cleared on RESET.

On NMOS, DF is unchanged when entering an interrupt of any kind. This can cause unexpected bugs in the interrupt handler if Decimal Mode is on when an interrupt occurs. On CMOS, DF is automatically cleared on interrupt. Upon returning from an interrupt, the processor restores the status register from the stack, including DF.


Memory Access

The address space that the 6502 uses is split into pages. There are 256 pages and each page is 256 bytes in size, ranging from page 0 to page 255.

In order to make up for the lack of registers, the 6502 includes a zero page addressing mode ($0000-$00FF) that uses only 1 address byte in the instruction instead of the 2 that are needed to address the full 64 KB of memory. This provides fast access to the first 256 bytes of RAM by using shorter instructions.

The stack is permanently located in page 1 ($0100-$01FF) and managed by the 8-bit stack pointer (S), with an initial value of $FF. It grows downward as data is pushed onto the stack. The stack has a 256-byte limit, and overflow occurs if not managed properly.

Instructions PHA and PHP push the accumulator and processor status onto the stack, while PLA and PLP pull them back. Subroutine calls with JSR store the return address on the stack, and RTS retrieves it to continue execution. Similarly, interrupts (BRK) push the program counter and status, while RTI restores them.

All I/O operations are memory-mapped. There are no port-based I/O instructions.


Half Cycles

The 6502 divides each clock cycle into two phases (ϕ1 and ϕ2):

  • During the ϕ1 half-cycle, no bus access occurs. This phase is dedicated to internal CPU operations.
  • During the ϕ2 half-cycle, the CPU accesses the external bus for memory reads/writes or I/O operations.

The use of half-cycles ensures that memory and I/O devices have predictable timing windows when the CPU will access the bus, while still allowing the CPU to perform internal operations in parallel.

Unlike most microprocessors, the 6502 does not make memory accesses on an "as needed" basis. It always does a fetch or store on every single clock cycle. When there isn't anything to be fetched or stored, a "garbage" fetch or store occurs. This is mainly of importance with the memory-mapped I/O devices:

  • On NMOS, when adding a carry to the MSB of an address, a fetch occurs at a garbage address. On CMOS, the last byte of the instruction is refetched.
  • On NMOS, when doing a fetch-modify-store instruction (INC, DEC, ASL, LSR, ROL, ROR), garbage is stored into the location during the "modify" cycle... followed by the "real" store cycle which stores the correct data. On CMOS, a second fetch is performed instead of a garbage store.


Pipelining

The 6502 CPU uses some sort of pipelining. If an instruction does not store data in memory on its last cycle, the processor can fetch the opcode of the next instruction while executing the last cycle. This is very primitive as the 6502 does not have an instruction cache nor even a prefetch queue. It relies on RAM to hold all program information.

As an example, the instruction EOR #$FF truly takes 3 cycles:

  • On the first cycle, the opcode $49 will be fetched
  • During the second cycle the processor decodes the opcode and fetches the parameter #$FF
  • On the third cycle, the processor will perform the operation and store the result in register A, but simultaneously it fetches the opcode for the next instruction

This is why the EOR instruction effectively takes only 2 cycles.

However, this pipelining only makes sense when looking at full cycles. If we break it down into half-cycles, there's no actual overlap. In fact, it's the other way around. If the previous instruction ends with a memory write, the CPU has to wait for a half-cycle before fetching the next instruction on the next ϕ2 half-cycle.


Adressing Modes

Addressing Mode Example Operation
Immediate LDA #$EA A ← $EA
Absolute LDA $0314 A ← M($0314)
Absolute,X LDA $0314,X A ← M($0314+X)
Absolute,Y LDA $0314,Y A ← M($0314+Y)
Zeropage LDA $02 A ← M($02)
Zeropage,X LDA $02,X A ← M($02+X)
Zeropage,Y LDA $02,Y A ← M($02+Y)
(Zeropage,X) LDA ($02,X) A ← M(PTR($02+X))
(Zeropage),Y LDA ($02),Y A ← M(PTR($02)+Y)


NMOS 6502 Instruction Set

Standard instructions

Cycles are shown in parenthesis for each opcode. p=1 if page is crossed. t=1 if branch is taken.

Mnemonic Addressing Modes Flags Operation Description
No arg A #$nn $nnnn $nnnn,X $nnnn,Y ($nnnn) $nn $nn,X $nn,Y ($nn,X) ($nn),Y rel N V - B D I Z C
ADC 69 (2) 6D (4) 7D (4+p) 79 (4+p) 65 (3) 75 (4) 61 (6) 71 (5+p) N V - - - - Z C A + M + CF → A, CF Add Memory to Accumulator with Carry
AND 29 (2) 2D (4) 3D (4+p) 39 (4+p) 25 (3) 35 (4) 21 (6) 31 (5+p) N - - - - - Z - A ∧ M → A "AND" Memory with Accumulator
ASL 0A (2) 0E (6) 1E (7) 06 (5) 16 (6) N - - - - - Z C CF ← /M7...M0/ ← 0 Arithmetic Shift Left
BCC 90 (2+t+p) - - - - - - - - Branch on CF = 0 Branch on Carry Clear
BCS B0 (2+t+p) - - - - - - - - Branch on CF = 1 Branch on Carry Set
BEQ F0 (2+t+p) - - - - - - - - Branch on ZF = 1 Branch on Result Zero
BIT 2C (4) 24 (3) N V - - - - Z - A ∧ M, M7 → NF, M6 → VF Test Bits in Memory with Accumulator
BMI 30 (2+t+p) - - - - - - - - Branch on NF = 1 Branch on Result Minus
BNE D0 (2+t+p) - - - - - - - - Branch on ZF = 0 Branch on Result Not Zero
BPL 10 (2+t+p) - - - - - - - - Branch on NF = 0 Branch on Result Plus
BRK 00 (7) - - - - - 1 - - PC + 2↓, [FFFE] → PCL, [FFFF] → PCH Force Interrupt
BVC 50 (2+t+p) - - - - - - - - Branch on VF = 0 Branch on Overflow Clear
BVS 70 (2+t+p) - - - - - - - - Branch on VF = 1 Branch on Overflow Set
CLC 18 (2) - - - - - - - 0 0 → CF Clear Carry Flag
CLD D8 (2) - - - - 0 - - - 0 → DF Clear Decimal Mode
CLI 58 (2) - - - - - 0 - - 0 → IF Clear Interrupt Disable
CLV B8 (2) - 0 - - - - - - 0 → VF Clear Overflow Flag
CMP C9 (2) CD (4) DD (4+p) D9 (4+p) C5 (3) D5 (4) C1 (6) D1 (5+p) N - - - - - Z C A - M Compare Memory and Accumulator
CPX E0 (2) EC (4) E4 (3) N - - - - - Z C X - M Compare Index Register X To Memory
CPY C0 (2) CC (4) C4 (3) N - - - - - Z C Y - M Compare Index Register Y To Memory
DEC CE (6) DE (7) C6 (5) D6 (6) N - - - - - Z - M - 1 → M Decrement Memory By One
DEX CA (2) N - - - - - Z - X - 1 → X Decrement Index Register X By One
DEY 88 (2) N - - - - - Z - Y - 1 → Y Decrement Index Register Y By One
EOR 49 (2) 4D (4) 5D (4+p) 59 (4+p) 45 (3) 55 (4) 41 (6) 51 (5+p) N - - - - - Z - A ⊻ M → A "Exclusive OR" Memory with Accumulator
INC EE (6) FE (7) E6 (5) F6 (6) N - - - - - Z - M + 1 → M Increment Memory By One
INX E8 (2) N - - - - - Z - X + 1 → X Increment Index Register X By One
INY C8 (2) N - - - - - Z - Y + 1 → Y Increment Index Register Y By One
JMP 4C (3) 6C (5) - - - - - - - - [PC + 1] → PCL, [PC + 2] → PCH Jump
JSR 20 (6) - - - - - - - - PC + 2↓, [PC + 1] → PCL, [PC + 2] → PCH Jump To Subroutine
LDA A9 (2) AD (4) BD (4+p) B9 (4+p) A5 (3) B5 (4) A1 (6) B1 (5+p) N - - - - - Z - M → A Load Accumulator with Memory
LDX A2 (2) AE (4) BE (4+p) A6 (3) B6 (4) N - - - - - Z - M → X Load Index Register X From Memory
LDY A0 (2) AC (4) BC (4+p) A4 (3) B4 (4) N - - - - - Z - M → Y Load Index Register Y From Memory
LSR 4A (2) 4E (6) 5E (7) 46 (5) 56 (6) 0 - - - - - Z C 0 → /M7...M0/ → CF Logical Shift Right
NOP EA (2) - - - - - - - - No operation No Operation
ORA 09 (2) 0D (4) 1D (4+p) 19 (4+p) 05 (3) 15 (4) 01 (6) 11 (5+p) N - - - - - Z - A ∨ M → A "OR" Memory with Accumulator
PHA 48 (3) - - - - - - - - A↓ Push Accumulator On Stack
PHP 08 (3) - - - 1 - - - - P↓ Push Processor Status on Stack
PLA 68 (4) N - - - - - Z - (S)↑ → A Pull Accumulator From Stack
PLP 28 (4) N V - B D I Z C (S)↑ → P Pull Processor Status From Stack
ROL 2A (2) 2E (6) 3E (7) 26 (5) 36 (6) N - - - - - Z C CF ← /M7...M0/ ← CF Rotate One Bit Left (Memory or Accumulator)
ROR 6A (2) 6E (6) 7E (7) 66 (5) 76 (6) N - - - - - Z C CF → /M7...M0/ → CF Rotate One Bit Right (Memory or Accumulator)
RTI 40 (6) N V - B D I Z C (S)↑ → P, (S)↑ → PCL, (S)↑ → PCH Return From Interrupt
RTS 60 (6) - - - - - - - - (S)↑ → PCL, (S)↑ → PCH, PC + 1 → PC Return From Subroutine
SBC E9 (2) ED (4) FD (4+p) F9 (4+p) E5 (3) F5 (4) E1 (6) F1 (5+p) N V - - - - Z C A - M - (1 - CF) → A Subtract Memory from Accumulator with Borrow
SEC 38 (2) - - - - - - - 1 1 → CF Set Carry Flag
SED F8 (2) - - - - 1 - - - 1 → DF Set Decimal Mode
SEI 78 (2) - - - - - 1 - - 1 → IF Set Interrupt Disable
STA 8D (4) 9D (5) 99 (5) 85 (3) 95 (4) 81 (6) 91 (6) - - - - - - - - A → M Store Accumulator in Memory
STX 8E (4) 86 (3) 96 (4) - - - - - - - - X → M Store Index X in Memory
STY 8C (4) 84 (3) 94 (4) - - - - - - - - Y → M Store Index Y in Memory
TAX AA (2) N - - - - - Z - A → X Transfer Accumulator to Index X
TAY A8 (2) N - - - - - Z - A → Y Transfer Accumulator to Index Y
TSX BA (2) N - - - - - Z - S → X Transfer Stack Pointer to Index X
TXA 8A (2) N - - - - - Z - X → A Transfer Index X to Accumulator
TXS 9A (2) - - - - - - - - X → S Transfer Index X to Stack Pointer
TYA 98 (2) N - - - - - Z - Y → A Transfer Index Y to Accumulator

Illegal instructions

Opcodes in red are unstable. Only 2 of those 7 opcodes ($8B, $AB) are actually unstable in the sense that they may produce a truly unpredictable result. The other 5 opcodes actually produce predictable results – but the conditions under which they do that and the produced results are a bit unexpected.

Mnemonic Combines Addressing Modes Flags Operation Description
No arg #$nn $nnnn $nnnn,X $nnnn,Y $nn $nn,X $nn,Y ($nn,X) ($nn),Y N V - B D I Z C
ANC (ANC2) AND + ASL/ROL 0B, 2B (2) N - - - - - Z C A ∧ M → A, NF → CF "AND" Memory with Accumulator then Move Negative Flag to Carry Flag
ARR AND + ROR 6B (2) N V - - - - Z C (A ∧ M) / 2 → A "AND" Accumulator then Rotate Right
ASR (ALR) AND + LSR 4B (2) 0 - - - - - Z C (A ∧ M) / 2 → A "AND" then Logical Shift Right
DCP (DCM) DEC + CMP CF (6) DF (7) DB (7) C7 (5) D7 (6) C3 (8) D3 (8) N - - - - - Z C M - 1 → M, A - M Decrement Memory By One then Compare with Accumulator
ISC (ISB, INS) INC + SBC EF (6) FF (7) FB (7) E7 (5) F7 (6) E3 (8) F3 (8) N V - - - - Z C M + 1 → M, A - M → A Increment Memory By One then SBC then Subtract Memory from Accumulator with Borrow
JAM (KIL, HLT) 02, 12, 22,

32, 42, 52,

62, 72, 92,

B2, D2, F2 (X)

- - - - - - - - Stop execution Halt the CPU
LAS (LAR) STA/TXS + LDA/STX BB (4+p) N - - - - - Z - M ∧ S → A, X, S "AND" Memory with Stack Pointer
LAX (LXA) LDA + LDX AB (2) AF (4) BF (4+p) A7 (3) B7 (4) A3 (6) B3 (5+p) N - - - - - Z - M → A, X Load Accumulator and Index Register X From Memory
NOP (DOP, TOP) 1A, 3A, 5A,

7A, DA, FA (2)

80, 82, 89,

C2, E2 (2)

0C (4) 1C, 3C, 5C,

7C, DC, FC (4+p)

04, 44, 64 (3) 14, 34, 54,

74, D4, F4 (4)

- - - - - - - - No operation No Operation
RLA ROL + AND 2F (6) 3F (7) 3B (7) 27 (5) 37 (6) 23 (8) 33 (8) N - - - - - Z C CF ← /M7...M0/ ← CF, A ∧ M → A Rotate Left then "AND" with Accumulator
RRA ROR + ADC 6F (6) 7F (7) 7B (7) 67 (5) 77 (6) 63 (8) 73 (8) N V - - - - Z C CF → /M7...M0/ → CF, A + M + CF → A Rotate Right and Add Memory to Accumulator
SAX (AXS, AAX) STA + STX 8F (4) 87 (3) 97 (4) 83 (6) - - - - - - - - A ∧ X → M Store Accumulator "AND" Index Register X in Memory
SBC (USBC) SBC + NOP EB (2) N V - - - - Z C A - M - ~CF → A Subtract Memory from Accumulator with Borrow
SBX (AXS, SAX) CMP + DEX CB (2) N - - - - - Z C (A ∧ X) - M → X Subtract Memory from Accumulator "AND" Index Register X
SHA (AHX, AXA) STA/STX/STY 9F (5) 93 (6) - - - - - - - - A ∧ X ∧ V → M Store Accumulator "AND" Index Register X "AND" Value
SHS (TAS, XAS) STA/TXS + LDA/TSX 9B (5) - - - - - - - - A ∧ X → S, S ∧ (H + 1) → M Transfer Accumulator "AND" Index Register X to Stack Pointer then Store Stack Pointer "AND" Hi-Byte In Memory
SHX (SXA, XAS) STA/STX/STY 9E (5) - - - - - - - - X ∧ (H + 1) → M Store Index Register X "AND" Value
SHY (SYA, SAY) STA/STX/STY 9C (5) - - - - - - - - Y ∧ (H + 1) → M Store Index Register Y "AND" Value
SLO (ASO) ASL + ORA 0F (6) 1F (7) 1B (7) 07 (5) 17 (6) 03 (8) 13 (8) N - - - - - Z C M * 2 → M, A ∨ M → A Arithmetic Shift Left then "OR" Memory with Accumulator
SRE (LSE) LSR + EOR 4F (6) 5F (7) 5B (7) 47 (5) 57 (6) 43 (8) 53 (8) N - - - - - Z C M / 2 → M, A ⊻ M → A Logical Shift Right then "Exclusive OR" Memory with Accumulator
XAA (ANE) TXA + AND 8B (2) N - - - - - Z - (A ∨ V) ∧ X ∧ M → A Non-deterministic Operation of Accumulator, Index Register X, Memory and Bus Contents


Opcodes

The 6502 follows a 3-3-2 opcode bit pattern. If we arrange the opcode table in a slightly different way than it is usually done, we can observe some interesting symmetries:

Opc Mnemonic
00 BRK
04 NOP zpg
08 PHP
0C NOP abs
10 BPL rel
14 NOP zpg,X
18 CLC
1C NOP abs,X
Opc Mnemonic
20 JSR abs
24 BIT zpg
28 PLP
2C BIT abs
30 BMI rel
34 NOP zpg,X
38 SEC
3C NOP abs,X
Opc Mnemonic
40 RTI
44 NOP zpg
48 PHA
4C JMP abs
50 BVC rel
54 NOP zpg,X
58 CLI
5C NOP abs,X
Opc Mnemonic
60 RTS
64 NOP zpg
68 PLA
6C JMP zpg
70 BVS rel
74 NOP zpg,X
78 SEI
7C NOP abs,X
Opc Mnemonic
80 NOP #
84 STY zpg
88 DEY
8C STY abs
90 BCC rel
94 STY zpg,X
98 TYA
9C SHY abs,X
Opc Mnemonic
A0 LDY #
A4 LDY zpg
A8 TAY
AC LDY abs
B0 BCS rel
B4 LDY zpg,X
B8 CLV
BC LDY abs,X
Opc Mnemonic
C0 CPY #
C4 CPY zpg
C8 INY
CC CPY abs
D0 BNE rel
D4 NOP zpg,X
D8 CLD
DC NOP abs,X
Opc Mnemonic
E0 CPX #
E4 CPX zpg
E8 INX
EC CPX abs
F0 BEQ rel
F4 NOP zpg,X
F8 SED
FC NOP abs,X
Opc Mnemonic
01 ORA (zpg,X)
05 ORA zpg
09 ORA #
0D ORA abs
11 ORA (zpg),Y
15 ORA zpg,X
19 ORA abs,Y
1D ORA abs,X
Opc Mnemonic
21 AND (zpg,X)
25 AND zpg
29 AND #
2D AND abs
31 AND (zpg),Y
35 AND zpg,X
39 AND abs,Y
3D AND abs,X
Opc Mnemonic
41 EOR (zpg,X)
45 EOR zpg
49 EOR #
4D EOR abs
51 EOR (zpg),Y
55 EOR zpg,X
59 EOR abs,Y
5D EOR abs,X
Opc Mnemonic
61 ADC (zpg,X)
65 ADC zpg
69 ADC #
6D ADC abs
71 ADC (zpg),Y
75 ADC zpg,X
79 ADC abs,Y
7D ADC abs,X
Opc Mnemonic
81 STA (zpg,X)
85 STA zpg
89 NOP #
8D STA abs
91 STA (zpg),Y
95 STA zpg,X
99 STA abs,Y
9D STA abs,X
Opc Mnemonic
A1 LDA (zpg,X)
A5 LDA zpg
A9 LDA #
AD LDA abs
B1 LDA (zpg),Y
B5 LDA zpg,X
B9 LDA abs,Y
BD LDA abs,X
Opc Mnemonic
C1 CMP (zpg,X)
C5 CMP zpg
C9 CMP #
CD CMP abs
D1 CMP (zpg),Y
D5 CMP zpg,X
D9 CMP abs,Y
DD CMP abs,X
Opc Mnemonic
E1 SBC (zpg,X)
E5 SBC zpg
E9 SBC #
ED SBC abs
F1 SBC (zpg),Y
F5 SBC zpg,X
F9 SBC abs,Y
FD SBC abs,X
Opc Mnemonic
02 JAM
06 ASL zpg
0A ASL A
0E ASL abs
12 JAM
16 ASL zpg,X
1A NOP
1E ASL abs,X
Opc Mnemonic
22 JAM
26 ROL zpg
2A ROL A
2E ROL abs
32 JAM
36 ROL zpg,X
3A NOP
3E ROL abs,X
Opc Mnemonic
42 JAM
46 LSR zpg
4A LSR A
4E LSR abs
52 JAM
56 LSR zpg,X
5A NOP
5E LSR abs,X
Opc Mnemonic
62 JAM
66 ROR zpg
6A ROR A
6E ROR abs
72 JAM
76 ROR zpg,X
7A NOP
7E ROR abs,X
Opc Mnemonic
82 NOP #
86 STX zpg
8A TXA
8E STX abs
92 JAM
96 STX zpg,Y
9A TXS
9E SHX abs,Y
Opc Mnemonic
A2 LDX #
A6 LDX zpg
AA TAX
AE LDX abs
B2 JAM
B6 LDX zpg,Y
BA TSX
BE LDX abs,X
Opc Mnemonic
C2 NOP #
C6 DEC zpg
CA DEX
CE DEC abs
D2 JAM
D6 DEC zpg,X
DA NOP
DE DEC abs,X
Opc Mnemonic
E2 NOP #
E6 INC zpg
EA NOP
EE INC abs
F2 JAM
F6 INC zpg,X
FA NOP
FE INC abs,X
Opc Mnemonic
03 SLO (zpg,X)
07 SLO zpg
0B ANC #
0F SLO abs
13 SLO (zpg),Y
17 SLO zpg,X
1B SLO abs,Y
1F SLO abs,X
Opc Mnemonic
23 RLA (zpg,X)
27 RLA zpg
2B ANC #
2F RLA abs
33 RLA (zpg),Y
37 RLA zpg,X
3B RLA abs,Y
3F RLA abs,X
Opc Mnemonic
43 SRE (zpg,X)
47 SRE zpg
4B ASR #
4F SRE abs
53 SRE (zpg),Y
57 SRE zpg,X
5B SRE abs,Y
5F SRE abs,X
Opc Mnemonic
63 RRA (zpg,X)
67 RRA zpg
6B ARR #
6F RRA abs
73 RRA (zpg),Y
77 RRA zpg,X
7B RRA abs,Y
7F RRA abs,X
Opc Mnemonic
83 SAX (zpg,X)
87 SAX zpg
8B XAA #
8F SAX abs
93 SHA (zpg),Y
97 SAX zpg,Y
9B SHS abs,Y
9F SHA abs,Y
Opc Mnemonic
A3 LAX (zpg,X)
A7 LAX zpg
AB LXA #
AF LAX abs
B3 LAX (zpg),Y
B7 LAX zpg,Y
BB LAS abs,Y
BF LAX abs,Y
Opc Mnemonic
C3 DCP (zpg,X)
C7 DCP zpg
CB SBX #
CF DCP abs
D3 DCP (zpg),Y
D7 DCP zpg,X
DB DCP abs,Y
DF DCP abs,X
Opc Mnemonic
E3 ISC (zpg,X)
E7 ISC zpg
EB SBC #
EF ISC abs
F3 ISC (zpg),Y
F7 ISC zpg,X
FB ISC abs,Y
FF ISC abs,X

Opcodes in bold are illegal. Opcodes in red are unstable.


Oddities

  • On NMOS, an indirect JMP will behave unexpectedly when the indirect address crosses a page boundary, because the 6502 does not add the carry to calculate the address of the high byte. For example, JMP ($19FF) will use the contents of $19FF and $1900 for the JMP address. On CMOS, this issue was fixed, at the cost of 1 additional cycle. In our example, JMP ($19FF) will use the contents of $19FF and $2000 for the JMP address.
  • Some instructions, particularly those involving branches or indexed addressing modes, incur an extra cycle if the processor has to cross a memory page boundary. This is problematic for time-sensitive code.
  • Conditional jumps are only 8-bit relative. And unconditional jumps are only 16-bit absolute.
  • ADC is the only command for addition. To perform an addition without carry, the carry flag must be cleared manually first. Same with SBC for subtract.
  • The CLV (Clear Overflow Flag) instruction exist but not the SEV (Set Overflow Flag) instruction.
  • The NOP instruction takes 2 full-cycles. This is the minimum amount of cycles an instruction can take.
  • The alternate NOPs are not created equal. Some have one- or two-byte operands (which they don't do anything with), and they take different amounts of time to execute.


Block Diagrams

Simple view

Mcs6502-block-diagram.svg

Detailed view

CPU 6502 Detailed Block Diagram.jpg


CPU Pinout

6502CPU Pinout.gif

Notes:

  • SYNC is an output signal. It is high at T0.
  • S.O. is an input signal, which stands for Set Overflow. It allows the hardware to affect VF independently of the software.
  • Some pins are modified in CPU variants.


Chip Variants

  • The ROR instruction didn't exist in the very earliest (pre-1977) chips.
  • The 6502 core used inside the NES is missing the Decimal Mode feature.
  • The 6507 CPU, used in the Atari VCS, has only 13 address lines. So it can only address 8KB instead of 64KB. It also lacks the IRQ and NMI interrupt lines.
  • The 6510 CPU, used in the Commodore 64, is a 6502 with an additional AEC pin that puts the bus in high impedance mode. It also includes a 6-bit I/O port that occupies addresses 0 and 1.
  • The 6502C used in Atari 8-bit computer range, adds an additional HALT pin. The 6502C is otherwise a regular NMOS 6502, not to be confused with the CMOS 65C02.
  • The CMOS 65C02 fixed multiple bugs of the original NMOS 6502, but also removed access to all illegal instructions. Some cycle counts have been modified and some extra instructions have been added. In fact, there are multiple implementations of the 65C02 (WDC 65C02, WDC 65C02S, Rockwell R65C02, CSG 65CE02, ...), each with its own variant of the instruction set.
  • The HuC6280, used in the PC-Engine gaming console, is an improved version of the CMOS 65C02.
  • The 65C816, used in the SNES and the Apple IIGS, is a 16-bit version of the 65C02. It contains a compatibillity mode, enabled by default upon reset, that makes it behave like a regular 65C02.
  • The Sony SPC700 sound CPU used inside the SNES also behaves similarly to a 6502 with some extensions. Source


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