Programming:Filling memory with a byte
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;; This code snippet will show one method to fill a block ;; of memory with a single data byte using Z80 assembly ;; language. ;;-------------------------------------------------- ;; HL = start address of block ld hl,&4000 ;; DE = HL + 1 ld e,l ld d,h inc de ;; initialise first byte of block ;; with data byte (&00) ld (hl),&00 ;; BC = length of block in bytes ;; HL+BC-1 = end address of block ld bc,&4000 ;; fill memory ldir ;;-------------------------------------------------- ;; For each iteration of the LDIR command: ;; ;; 1. This command will copy the byte from the memory ;; address pointed to by HL to the memory address pointed to by DE. ;; i.e. (DE) = (HL). ;; 2. Then HL and DE will be incremented. BC will be decremented. ;; ;; ;; For the first byte: ;; ;; HL = start ;; DE = start+1 ;; BC = length ;; (HL)=0 ;; ;; For the second byte: ;; ;; HL = start + 1 (initialised to 0 by the previous iteration) ;; DE = start + 2 ;; BC = length - 1 ;; ;; For the third byte: ;; ;; HL = start + 2 (initialised to 0 by the previous iteration) ;; DE = start + 3 ;; BC = length - 2 ;; ;; etc....