Difference between revisions of "Programming:Filling memory with a byte"
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; Define the region of RAM to be filled | ; Define the region of RAM to be filled | ||
− | ld | + | ld hl,YOUR_BYTE_1*&100 + YOUR_BYTE_2 ; Use HL or whichever 16-bit register you prefer |
− | + | ld de,LENGTH_TO_FILL/2 ; divided by 2 because DE is 2 bytes wide and PUSH pushes both | |
− | ld de,LENGTH_TO_FILL/2 ; divided by 2 because DE is 2 bytes wide and PUSH pushes both | + | |
; Set up a fast 16-bit loop counter | ; Set up a fast 16-bit loop counter |
Revision as of 12:52, 14 December 2012
Using LDIR
From the The Unofficial Amstrad WWW Resource
;; This code snippet will show one method to fill a block ;; of memory with a single data byte using Z80 assembly ;; language. ;;-------------------------------------------------- ;; HL = start address of block ld hl,&4000 ;; DE = HL + 1 ld e,l ld d,h inc de ;; initialise first byte of block ;; with data byte (&00) ld (hl),&00 ;; BC = length of block in bytes ;; HL+BC-1 = end address of block ld bc,&4000 ;; fill memory ldir ;;-------------------------------------------------- ;; For each iteration of the LDIR command: ;; ;; 1. This command will copy the byte from the memory ;; address pointed to by HL to the memory address pointed to by DE. ;; i.e. (DE) = (HL). ;; 2. Then HL and DE will be incremented. BC will be decremented. ;; ;; ;; For the first byte: ;; ;; HL = start ;; DE = start+1 ;; BC = length ;; (HL)=0 ;; ;; For the second byte: ;; ;; HL = start + 1 (initialised to 0 by the previous iteration) ;; DE = start + 2 ;; BC = length - 1 ;; ;; For the third byte: ;; ;; HL = start + 2 (initialised to 0 by the previous iteration) ;; DE = start + 3 ;; BC = length - 2 ;; ;; etc....
Using the stack
This method write bytes at a considerably faster rate by exploiting the speed of the stack pointer (SP) moving through RAM and its 2-byte steps. It is especially good for very rapidly clearing the screen.--Db6128 (talk) 06:29, 13 December 2012 (EET)
; Save the stack pointer ld (SAVE_SP),sp ; Only remove if you're sure you don't need the stack ld sp,FINAL_ADDRESS+1 ; e.g. to fill from &C000 to &FFFF (&4000 bytes), set SP to &FFFF+1 = &0000 ; Define the region of RAM to be filled ld hl,YOUR_BYTE_1*&100 + YOUR_BYTE_2 ; Use HL or whichever 16-bit register you prefer ld de,LENGTH_TO_FILL/2 ; divided by 2 because DE is 2 bytes wide and PUSH pushes both ; Set up a fast 16-bit loop counter dec de ; This method takes advantage of the fact that DJNZ leaves B as 0, which subsequent DJNZs see as 256 ld b,e ; B = (length/2) MOD 256, so 0 = a 512-byte block inc b ; D = the number of 512-byte blocks to write, or just = 1 if the length is <512 inc d ; Of course, if you know the length ahead of run-time, you can set B and D directly in your ASM ; Fill the memory PUSHLOOP: push hl ; Writes HL to (SP-2) and DECs SP by 2. ; For even more speed, use multiple PUSH HLs in a row (I like 8, = &10 bytes) and adjust counters to match djnz PUSHLOOP dec d jr nz,PUSHLOOP ; Restore the stack pointer SAVE_SP equ $+1 ld SP,&9999 ; &9999 will be replaced by the actual previous value